Question

Length of a rectangle is 8m less than twice its breadth. If the perimeter of the rectangle is 56m. find its length and breadth

Answer 1

let length be, l

let breadth be , b

let perimeter be, p

l= 2*b-8

p= 2(l+b)

put value of l

p=2(2*b-8+b)

p=4*b-16+2*b

put p = 56

56+16=4*b-2*b

72=2*b

72/2=b

b=36m

put value of b in l=2b-8

l=2*36-8

l=72-8

l=64

Answer 2

$\bold{\Huge{\underline{\boxed{\sf{\purple{ANSWER\::}}}}}}$

$\bold{\Large{\underline{\sf{\green{Given\::}}}}}$

Length of a rectangle is 8m less than twice its breadth. If the perimeter of the rectangle is 56m.

$\bold{\Large{\underline{\rm{\red{To\:find\::}}}}}$

Its length & breadth.

$\bold{\Large{\underline{\rm{\orange{Explanation\::}}}}}$

Let the breadth be R &

Let the length be (2R - 8)m

We have,

Perimeter of the rectangle is 56m.

We know that formula of the perimeter of rectangle:

→ 2(Length + Breadth)

A/q

→ 2(2R - 8) + R) = 56m

→ 4R - 16 + 2R = 56

→ 4R + 2R = 56 + 16

→ 6R = 72

→ R = $\bold{\cancel{\frac{72}{6} }}$

→ R = 12m

Thus,

• The length of a rectangle= (2×12 - 8)m = (24 - 8)m = 16m

• The breadth of a rectangle= 12m