Question

Length of a rectangular ground is double than its breadth. If its perimeter is 300 metres find the length and breadth of the rectangle​

Answer 1

Answer :

›»› The length and the breadth of the rectangle is 100 m and 50 m respectively.

Given :

• Length of a rectangle ground is double than its breadth.
• Perimeter of a rectangle = 300 m.

To Find :

• The length and breadth of the rectangle = ?

Solution :

Let us assume that, the breadth of a rectangle is x m.

As it is given that, the length of a rectangle ground is double than its breadth.

→ Length = 2x

As we know that

→ Perimeter of a rectangle = 2(l + b)

→ 300 = 2(2x + x)

→ 300 = 2 * 2x + 2 * x

→ 300 = 4x + 2 * x

→ 300 = 4x + 2x

→ 300 = 6x

→ x = 300 ÷ 6

→ x = 50

Therefore,

The length and the breadth of rectangle will be,

• Breadth = x = 50 m.
• Length = 2x = 2 * 50 = 100 m.

Hence, the length and breadth of the rectangle is 100 m and 50 m respectively.

Verification :

→ Perimeter of a rectangle = 2(l + b)

→ 300 = 2(100 + 50)

→ 300 = 2 * 100 + 2 * 50

→ 300 = 200 + 2 * 50

→ 300 = 200 + 100

→ 300 = 300

Here, LHS = RHS

Hence Verified !

Answer 2

Answer:

$\huge \bf \: required \: answer$

Let the breadth be x

Length = 2x

Perimeter = 300 m

$perimeter \: = 2(l + b)$

$300 = 2(2x + x)$

$300 = 2 \times 2x +2 \times x$

$300 = 4x + 2 \times x$

$300 = 6x$

$x = \frac{300}{6}$

$x = 50 \: m$

$2x = 2 \times 50 = 100 \: m$

$\therefore \: l \: = 100 \: m \\ b \: = 50 \: m$

Verification

$perimeter \: = 2(l + b)$

$300 = 2(100 + 50)$

$300 = 2 \times 150$

$300 = 300$

LHS = RHS

Hence verified