Question

Length of a rectangular park is 40 metres more than its breadth. Area of the park is 2304 square metres.

Answer 1

Let the breadth of the rectangular park = x metres

Therefore, length of the rectangular park = (x+ 40) metres.

So, area of the rectangular park = (x + 40) ∙ x square metres

According to the problem we get,

(x + 40) ∙ x = 2304

or, x^2 + 40x = 2304

or, x2  + 40x - 2304 = 0 .................... (i)

OR,

Let the length of the rectangular park = x metres

Therefore, the breadth of the rectangular park =(x - 40) metres

Area of the rectangular park = x(x - 40) square metres

According to the problem we get,

x(x - 40) = 2304

or,x2  - 40x - 2304 = 0 ....................  (ii)

Both of (i) and (ii) are quadratic equations.

Answer 2

Let the breadth of the rectangular park be 'x' mts.

⇒ length of the rectangular park = (x+ 40) mts.

∴ area of the rectangular park = length x breadth

                                                 = (x + 40) ∙ x m²

According to the problem,

(x + 40) ∙ x = 2304

⇒ x² + 40x = 2304

⇒x²  + 40x - 2304 = 0 

                                                (OR)

Let the length of the rectangular park be 'x' mts.

∴ The breadth of the rectangular park =(x - 40) mts

Area of the rectangular park = x(x - 40) m²

According to the problem,

x(x - 40) = 2304

⇒x²  - 40x - 2304 = 0.

Hope it helps ^_^