Question

А Length of a rod measure in an experiment was found to be 2.88m, 2.46 m, 2.49m) 2.5om, 2:48 m find average length, absolute error, Relative error percentage error​

Answer 1

Answer:

observations = 2.88m, 2.46m, 2.49m, 2.5m, 2.48m

average = (2.88+2.46+2.49+2.50+2.48)/5

= 2.56m

absolute error = |2.88-2.56| = 0.32

= |2.46-2.56| = 0.1

= |2.49-2.56| = 0.7

= |2.50-2.56| = 0.6

= |2.48-2.56| = 0.8

mean absolute error = (0.32+0.1+0.7+0.6+0.8)/5 = 0.5

relative error = 2.56 ± 0.5

percentage error = 0.5/2.56 ×100 = 1/5 ×100 = 20%