Question

length of a room is (2m+n-c) and breadth is (5n+3m+3c) find its area and perimeter​

Answer 1

Answer:

perimeter =10m+12n+4c,area=6$m^{2}$+5$n^{2}$-3$c^{2}$

Step-by-step explanation:

length of room =(2m+n-c)

breadth=(5n+3m+3c)

perimeter = 2(l+b)

2(2m+n-c+(5n+3m+3c))

2(2m+3m+n+5n+3c-c)

2(5m+6n+2c)

2(5m)+2(6n)+2(2c)

10m+12n+4c

perimeter=10m+12n+4c

area=l×b

2m+n-c×5n+3m+3c

2m(3m)+n(5n)-c(3c)

6$m^{2}$+5$n^{2}$-3$c^{2}$

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