Length of a room is 3 times its height and breadth is 1 1/2 times it’s height. The cost of whitewashing the walls at the rate of ₹1.50 per sq. m is ₹216. Find the dimensions of the room.
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22
H is the height of the room
L=3H
B=3H/2
AREA OF THE TWO WALLS ON THE LENGTH SIDE =2*L*H
AND ON THE BREADTH SIDE =2*B*H
AREA OF WALL=2(L+B)H = 2(3H+3H/2)H = 2(6H/2+3H/2)H
=2H*9H/2=9H^2
PAINTED AREA=216/1.50= 144m^2
THEREFORE, 9H^2=144m^2
= H^2=16
= H=4m
length=3H=12m
breadth=3H/2=6m
dimensions= 12m*6m*4m
L=3H
B=3H/2
AREA OF THE TWO WALLS ON THE LENGTH SIDE =2*L*H
AND ON THE BREADTH SIDE =2*B*H
AREA OF WALL=2(L+B)H = 2(3H+3H/2)H = 2(6H/2+3H/2)H
=2H*9H/2=9H^2
PAINTED AREA=216/1.50= 144m^2
THEREFORE, 9H^2=144m^2
= H^2=16
= H=4m
length=3H=12m
breadth=3H/2=6m
dimensions= 12m*6m*4m
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Hi this is the answer hope it helps you:-)
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