Question

length of an isosceles triangle is 3/2 times its base. its perimeter is 40 cm.find lenth of equal sides

Answer 1

Step-by-step explanation:

Let the base of the triangle be x cm

then, length of equal sides = 3x/2

Therefore perimeter = 40 cm

         ⇒ x + 3x/2+3x/2 = 40 cm

                     ⇒ x + 3x = 40 cm

                          ⇒ 4x = 40 cm

x = 10 cm

Now,

Length of equal sides = 3x/2

                                    = 3/2 × 10

                                    = 3 × 5

                                    =15 cm

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Answer 2

Answer:

If length of one of its equal side is x.

Then, base = 3x/2

ATQ

x + x + 3x/2 = 40

7x = 80

x = 80/7

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