Question

length of base of a triangle is 2 more than its height . if area is 48sq cm , form a quadratic equations to find the base and height?​

Answer 1

Step-by-step explanation:

h=b

area= √s(a+1) (a+1) (a+1)

2h²=48

H²=48/2

h²=24

h*h = 4.4

Answer 2

Answer:

h²+2h-96=0

Step-by-step explanation:

$given \\ b = 2 + h \\ area = 48m {}^{2} \\ we \: know \: that \\ area = \frac{1}{2} b \times h \\ so \: as \: per \: situation \\ b = 2 + h \\ area = \frac{1}{2} h \times (h + 2) = 48 \\ h ^{2} + 2h - 96= 0$