Question

length of cuboid = (x²-2)
breadth of cuboid = (2x+4)
height of cuboid = (x-3)
Volume??
Can someone pls tell the correct answer???​

Answer 1

Step-by-step explanation:

ANSWER

Let length, breadth and height of cuboid be 2x, 3x2x,3xand 4x4x respectively.

Now,

Surface area of cuboid = 2 \left( lb + bh + hl \right) = 208 \; {cm}^{2} \quad \left( \text{Given} \right)=2(lb+bh+hl)=208cm2(Given)

\therefore 2 \left( 2x \times 3x + 3x \times 4x + 4x \times 2x \right) = 208∴2(2x×3x+3x×4x+4x×2x)=208

6 {x}^{2} + 12 {x}^{2} + 8 {x}^{2} = 1046x2+12x2+8x2=104

\Rightarrow {x}^{2} = \cfrac{104}{26}⇒x2=26104

\Rightarrow x = \sqrt{4} = 2⇒x=4=2

As we know that,

Volume of cuboid 

= l \times b \times h \\ = 2x \times 3x \times 4x \\ = 24 {x}^{3} \\ = 24 \times {2}^{3} \\ = 24 \times 8 = 192 \; {cm}^{3}=l×b×h=2x×3x×4x=24x3=24×23=24×8=192cm

Answer 2

Answer:

i hope this helps the value of x is not given so volume cannot be in numbers...