LENGTH OF DIAGONAL OF A RECTANGLE IS 5 CM.THE LENGTH OF PERPENDICULAR OF A BREADTH OF RECTANGLE FROM INTERSECTING POINT BETWEEN 2 DIAGONALS IS 2CM. WHAT IS THE LENGHT OF BREADTH (MEASUREMENT)
Answers
Answer :
Solution : let us suppose the diagonal be DB, Breadth be BC and the perpendicular to breadth to point where diagonals intersect be FE.
BEF forms a right-angled triangle.
By pythagoras theorem,
(A)^2+(B)^2=(C)^2
therefore, (BE)^2+(EF)^2=(BF)^2
BF = 5 ÷ 2
=2.5cm
(BE)^2+(2)^2=(2.5)^2
(BE)^2=6.25 - 4
BE = √2.25
Therefore, BE = 1.5cm
Breadth = 1.5 × 2 = 3cm
Therefore, Breadth is 3cm
Step-by-step explanation : Here we have taken the rectangle as rectangle ABC and it's diagonal is BD which is 5cm. The length of segment FE which is perpendicular to breadth BC is 2cm. Here we can use pythagorean theorem to find the half of it's breadth which is BE. When we put the values we'll get the answer as 1.5cm which is the half of the breadth so adding it by itself will give us the answer as 3cm.
