Question

length of equal sides of an isosceles is 3/2 times its base.Its perimeter is 40 cm.Find length of equal sides.​

Answer 1

Step-by-step explanation:

let length of base be x

length of equal sides of triangle = 3/2 x

$\frac{3}{2} x + \frac{3}{2} x + x = 40 \\ 3x + x = 40 \\ 4x = 40 \\ x = 10 \\ \\ so \: length \: of \: equal \: sides \: = \frac{3}{2} \times 10 = 15cm$

Answer 2

Answer:

Step-by-step explanation:

Let the equal sides of the isosceles triangle be x and the unequal third side be y

So x=3/2y

Perimeter is 40cm

So,

3/2y+3/2y+y=40

3y+3y+2y/2=40

8y/2=40

y=10

so we know that x=3/2y

x=3/2*10

x=15cm

As we assumed that both the equal sides would be x ,so the measure of the other would also be 15cm.