Question

Length of one of the equal sides of an isosceles triangle is 4 cm. If its be is 2 cm then what is its area? (a)√15cm 2 (b) √13cm 2 (c) √12cm 2 (d) √14cm 2

Answer 1

Answer:

(a)√15cm 2

Step-by-step explanation:

Given: base BC = 2

The length of the other equal sides AB and AC are 4 cm.

So, to the find height AD, we need to apply Pythagoras theorem on triangle ABD.

Hence, (Hypotenuse)sqar = (Height) sqar + (Base/2)sqar

(AB) sqar = (AD) sqar + (BD) sqar

4 sqar = (AD) sqar + 1sqqr

16 = (AD) sqar + 1

(AD) sqar = 16 - 1 = 15

AD = √15cm

Now, area of the triangle = 1/2 (Base * Height)

= 1/2 * BC * AD

= 1/2 * 2 * √15

= √15cm sqar

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