Question

Length of one room is 15m 17cm and breadth is 9m 2cm. Find the minimum number of tiles which should be required of this room

Answer 1

Answer:814

Step-by-step explanation:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. Area of each tile = (41 x 41) cm2.

Therefore required no. of tiles = (1517×902)/41×41

Answer 2

Answer:

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.

Area of each tile = (41 x 41) cm^2.

Required number of tiles =

$( \frac{1517 \times 902}{41 \times 41} ) = 814$

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