length of parallel side of trapezium is 18 and 24 if area is 210 find the height
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trapezium's area = 1/2×[ parallel side of length ]× height so height = 210/(18×24)
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Solution 1
For a Trapezium
Base 1 = 18
Base 2 = 24
Height = ?
Area = (Base 1 +Base 2)/2 * Height
210 = (18 + 24) / 2 * Height
210 = 42/2 * Height
210 = 21 * Height
210/21 = Height
10 = Height
Height = 10
Solution 2
For a Trapezium
Area = 210 sq. unit
Base 1 = 18
Base 2 = 24
Height = (2 * Area) / (Base 1 + Base 2)
= (2 * 210) / (18 + 24)
= 420 / 42
Height = 10
If you are satisfied with the solution, please mark my answer as the brainliest.
For a Trapezium
Base 1 = 18
Base 2 = 24
Height = ?
Area = (Base 1 +Base 2)/2 * Height
210 = (18 + 24) / 2 * Height
210 = 42/2 * Height
210 = 21 * Height
210/21 = Height
10 = Height
Height = 10
Solution 2
For a Trapezium
Area = 210 sq. unit
Base 1 = 18
Base 2 = 24
Height = (2 * Area) / (Base 1 + Base 2)
= (2 * 210) / (18 + 24)
= 420 / 42
Height = 10
If you are satisfied with the solution, please mark my answer as the brainliest.
sonika9910:
length of two parallel side is trapezium is 25 and 45 and other side are equal and length of each side is 15 find area of trapezium and the length of digonal
In order to answer this question I need to attach an image file but it cannot be attached in the comments
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