Question

Length of rectangle is 5m less than twice its breadth if the perimeter of that rectangle is 62 m find its length and breadth

Answer 1

Let breadth be B
Then, length, L = 2B - 5

Given, perimeter = 62
2(L+B) = 62
2(2B - 5 + B) = 62
3B = 31+5 = 36
B = 12 m

L = 2×12-5 = 19 m

Answer 2

Given : Length of rectangle is 5m less than twice its breadth if the perimeter of that rectangle is 62 m

To find : The length and breadth of the rectangle.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the length and breadth of the rectangle)

Let, the breadth of the rectangle = x metres

So, the length of the rectangle will be :

= (2 × x) - 5

= (2x - 5) metres

The perimeter of the rectangle :

= 2 × (length + breadth)

= 2 × (2x - 5 + x)

= 2 × (3x - 5)

= (6x - 10) metres

According to the data mentioned in the question,

6x - 10 = 62

6x = 62 + 10

6x = 72

x = 72/6

x = 12

So, the breadth of the rectangle = x metres = 12 metres

And, the length of the rectangle = (2x - 5) = [(2 × 12) - 5] = (24 - 5) = 19 metres

Hence, the length of the rectangle is 19 metres and the breadth of the rectangle is 12 metres.