Question

length of rectangle is 8 cm and each of it’s diagonals measures 10 cm find its breadth

Answer 1

We know, length and breadth of rectangle are perpendicular to each other, then



By Pythagoras theorem,

length² + breadth² = diagonal²

8² + breadth² = 10²

Breadth² = 100 - 64

breadth = √36 = 6 cm




I hope this will help you


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Answer 2

Given:

• The length of the rectangle = 8 cm
• Each diagonal of the rectangle = 10 cm

To Find:

• The breadth of the rectangle

Solution:

• First, draw a figure using the given data.
• Consider triangle ABC.
• Triangle ABC is a right-angled triangle, so applying Pythagoras theorem.
• We get,
• $AB^2+BC^2=AC^2$
• In the above formula AB = Diagonal of the rectangle, BC = the breadth of the rectangle, and AC = the length of the rectangle.
• $BC^2=AC^2-AB^2$
• BC = $\sqrt{AC^2-AB^2}$
• BC = √100-64
• BC = √36
• BC = 6 cm.

∴ The breadth of the rectangle = 6 cm.