Question

Length of rectangular field is twice its breadth perimeter =60m what are its dimensions

Answer 1

Let the breadth of rectangular field be x m,


So, Length of rectangular field would be 2x m according to the question.





Formula, perimeter of rectangle = 2( length + breadth )


Given, perimeter of rectangular field = 60 m



= > 2( breadth + length ) = 60 m

= > ( x + 2x ) = 30 m

= > 3x = 30 m

= > x = 10 m




$\:$

Hence,
Breadth of rectangular field = x m = 10 m
Length of rectangular field = 2x m = 2( 10 m )= 20 m

Answer 2

$\bold {\huge {Solutions :-}}$

$\bold {Let}$ the $\bold {breadth}$ of rectangular field be $\bold { x }$

$\bold {So,}$
$\bold {Length~ =~ 2x}$

We know $\bold {perimeter ~of ~rectangle }$
$\bold {= ~2( length + breadth ) }$

$\bold {Given,}$
$\bold {Perimeter~ of~ rectangular}$ field
$\bold { = ~60 m}$

$\bold {=>~ 2( breadth + length ) ~= ~60 m}$

$\bold {= > 2( x + 2x ) = 60 }$

$\bold {= > 2x+4x = 60 }$

$\bold {=>6x = 60 }$

$\bold {= > x = 10 }$

$\bold {Hence, }$

$\bold {Breadth ~ =~ x ~= ~10 m}$
$\bold {Length ~ = ~2x ~= ~2( 10 m )~=~ 20 m}$