Math, asked by jayanttekwani, 9 months ago

Length of tape required to cover the edges of a semicircular disc of radius 10 cm is
i. 62.8 cm ii. 51.4 cm iii. 31.4 cm iv. 15.7 cm

Answers

Answered by bkpanda7015207073
24

length of tape required to cover the edges of semicircular disc of radius 10cm=1/2 x 2πr

length of tape required to cover the edges of semicircular disc of radius 10cm=1/2 x 2πr1/2 x 2 x 3.14 x 10 = 51.4 cm

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Answered by kunalky3033
24

ans 3

we know that area of circle is 2πr

so there is semi circle so it will be πr

length of tape requeried to cover the semi crcular edge= πr

given= r = 10

= 3.14×10.

= 31.40

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