Question

Length of the e.coli is 1.36mm.no of basepairs in ecoli?

Answer 1

Given :

Let the length of e.coli DNA is 1.36mm/1.36×10^3m

And distance between two consecutive (bp) 

 is 

0.34 ×^-9m 

 

Let 

Length of DNA =no. of Base pairs ×distance between consecutive (bp ) 

1.36×10^3m =no. Of Base pairs ×0.34×10^-9m

No of Base pairs =1.36×10^3÷0.34×10^-9

By solving it 

No of Base pairs =4×10^6m

MARK BRAINLIEST....