Question

Find the value of Rydberg's constant if the energy of electron in second orbit in hydrogen atom is -3.4 eV.
(Ans: 1.095 x 10⁻⁷ m⁻¹ )

Answer 1

it would be -60.742 thats my answer

Answer 2

Hello Dear,

● Answer -

Rh = 2.18×10^-18 J

● Explanation -

# Given -

E = -3.4 eV = -3.4×1.6×10^-19 J

# Solution -

Energy of electron in nth orbit of an element with atomic number Z is given by -

E = Rh.Z²/n²

For electron in 2nd orbit of hydrogen, Z = 1 & n = 2, E = -3.4 eV

-3.4×1.6×10^-19 = Rh × 1² / 2²

Rh = -3.4×1.6×10^-19 × 4

Rh = 2.18×10^-18 J

Therefore, value of Rydberg constant is 2.18×10^-18 J .

Hope you understand..