Question

Length of the fence of a trapezium shaped field abcd is 120 m. If bc = 48 cm, cd = 17 m and ad = 40 m, find the area of this field. Side ab is perpendicular to the parallel sides ad and bc​

Answer 1

Answer:

Given: BC = 48 m, CD = 17 m, AD = 40 m and perimeter = 120 m

Perimeter of trapezium ABCD = AB + BC + CD + DA

120 = AB + 48 + 17 + 40

120 = AB = 105

AB = 120 105 = 15 m

Area of the field = *(BC + AD)x AB 2

(48+ 40)x15 = , = 660 m2 x 88×15

Hence, area of the field ABCD is 660 m2.

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