Length of the shadow of a 5 meter high pole is 5 meters at 9.45 am in the
morning. Then, what is the angle of elevation of the Sun rays with the ground at
the time?
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2
Answer:
45°
Step-by-step explanation:
From the figure,
Height of pole (AB) = 5m
Length the of the shadow ( BC ) = 5m
Let the angle of elevation be 'x'
In triangle ABC,
<B = 90°
tan x = AB/BC
tan x = 5/5
tan x = 1
tan x = tan45°
Therefore, x = 45°
The angle of elevation of the Sun rays with the ground at the time is 45°.
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Step-by-step explanation:
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