Length of the tangent to a circle feom a point 17 cm and feom its center is 8cm then radius of circle ia
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Answer: 15
Step-by-step explanation:
Given : A circle with center O. PQ is the tangent ,PQ=17 and OP=8
To Find: OQ
Solution : In ∆ POQ angle OQP=90°
So, OQ=√ PQ^2 - OP^2
=√17^2 - 8^2
= √ 289 - 64
= √ 225
= 15
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