Length of the wite is 50cm and radius 0.5mm find the resistivity of wire if wire if its resistance is 30hm
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Answered by
2
we know that r=resistivity *l/A
where R is Resistance l is the length of wire and a is the cross sectional area
hence,resistivity = r*A/l
now, length is 50/100=0.5m and radius is 5*10^-4 m
so, resistivity = (30*(22/7*(5*10^-4)*(5*10^-4)))/0.5
=(30*(22/7*(25*10^-8))/0.5
=(30*(78.5*10^-8))/0.5
=(2355*10^-8)/0.5
=4710*10^-8 ohm/cm
where R is Resistance l is the length of wire and a is the cross sectional area
hence,resistivity = r*A/l
now, length is 50/100=0.5m and radius is 5*10^-4 m
so, resistivity = (30*(22/7*(5*10^-4)*(5*10^-4)))/0.5
=(30*(22/7*(25*10^-8))/0.5
=(30*(78.5*10^-8))/0.5
=(2355*10^-8)/0.5
=4710*10^-8 ohm/cm
Answered by
3
R = ρl/A
ρ = R x A / l
ρ = 30 x 3.14 x 0.5 x 10⁻³ x 0.5 x 10⁻³ / 50 x 10⁻²
ρ = 23.55 x 10⁻⁶ x 10² / 50
ρ = 23.55 x 10⁻⁴ / 50
ρ = 0.471 x 10⁻⁴
ρ = 4.71 x 10⁻⁵ ohm/cm
ρ = R x A / l
ρ = 30 x 3.14 x 0.5 x 10⁻³ x 0.5 x 10⁻³ / 50 x 10⁻²
ρ = 23.55 x 10⁻⁶ x 10² / 50
ρ = 23.55 x 10⁻⁴ / 50
ρ = 0.471 x 10⁻⁴
ρ = 4.71 x 10⁻⁵ ohm/cm
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