Question

lengths of diagonal of rhoms 30 and 40 cm find side

Answer 1

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✴here is your answer ✴
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Let ABCD be a rhombus with AC and BD as its diagonals.
We know that the diagonals of a rhombus bisect each other at right angles.
Let O be the intersecting point of both the diagonals.
Let AC=30cm and BD=40cm
OA=AC/2
OA= 30/2=15cm
OB=BD/2
OB=40/2=20cm
In rt.ΔAOB by Pythagoras theorem we have
AB²=OA²+OB²
=(15)²+(20)²
=225+400
=625
AB=25cm
Hence, each side of the rhombus is of length 25cm
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I hope you understand

Answer 2

As we know that diagonals of rhombus bisects each other at 90°

So, here,

(30/2)² +(40/2)² =side²

(15)² +(20)² =side²

225 +400 =side²

625 =side²

√625 =side

25 =side

Then, lenght of side is 25 cm



I hope this will help you


-by ABHAY