Lens of focal length 40 cm and another of –20 cm. Write the nature and
power of each lens.
Answers
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Explanation:
Power of 1st lens=100/40=+2.5D Convex
Power of 2nd lens=100/-20=-5D Concave
Therefore,
Net power=2.5-5= -2.5D Concave
Answered by
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Answer:
Positive the focal length positive the power
The lens used is convex lens
Power=1/focal length(in metres)
Power=1/0.4=2.5Dioptres
Negative the focal lenth negative the power
Lens used is concave lens
Power=1/f
Power= -1/0.2= - 5Dioptres
Hope this helps you
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