Math, asked by Anonymous, 11 months ago

Leslie analyzed the graph to determine if the function it represents is linear or non-linear. First she found three points on the graph to be (–1, –4), (0, -3), and (2, 5). Next, she determined the rate of change between the points (–1, –4) and (0, -3) to be mc017-2.jpg and the rate of change between the points (0, -3) and (2, 5) to be mc017-3.jpg. Finally, she concluded that since the rate of change is not constant, the function must be linear. Why is Leslie wrong?

Answers

Answered by sushmaag2102
7

Answer:

Finally as the rate of change is not the same, so those points can not be on a linear function.

Step-by-step explanation:

Leslie analyzed the graph to determine if the function it represents is linear or non-linear.

First, she took some points on the graph such as (–1,–4), (0,-3), and (2,5).

Next, she determined the rate of change between the points (–1,–4) and (0,-3) to be \frac{- 3 + 4}{0 + 1}  = 1.

And the rate of change between the points (0, -3) and (2, 5) to be \frac{5 + 3}{2 - 0} = 4.

Therefore, finally, as the rate of change is not the same, so those points can not be on a linear function. (Answer)

Answered by Anonymous
5

Answer:

The answer is her conclusion is wrong. If the rate of change is not constant, then the function cannot be linear.

Step-by-step explanation:

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