Question

Let 13 and 273 are the hcf and lcm of two numbers respectively, and if one of them is less than 140 and greater than 60 then what will be that number? A. 121

Answer 1

Let 13 and 273 are the hcf and lcm of two numbers respectively, and if one of them is less than 140 and greater than 60 then what will be that number? A. 121

Answer 2

Answer:91

Step-by-step explanation:

Let those 2 numbers be p and q .

We are given that HCF (p, q) = 13 and

LCM (p, q) = 273.

We know that product of numbers = HCF × LCM

Hence, p × q = 13 × 273

⇒ p × q = 13 × 13 × 3 × 7

P cannot be 13 × 3 or 13 × 13 or 7 × 3 or 13 or 3 or 7 as these numbers do not come between 60 and 140.

Hence we can say that p = 13 × 7 = 91