Question

Let 2z^2-2iz-5=0 find z

Answer 1

Step-by-step explanation:

Simplifying

z2 + 2iz + -5 = 0

Reorder the terms:

-5 + 2iz + z2 = 0

Solving

-5 + 2iz + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + 2iz + 5 + z2 = 0 + 5

Reorder the terms:

-5 + 5 + 2iz + z2 = 0 + 5

Combine like terms: -5 + 5 = 0

0 + 2iz + z2 = 0 + 5

2iz + z2 = 0 + 5

Combine like terms: 0 + 5 = 5

2iz + z2 = 5

Add '-1z2' to each side of the equation.

2iz + z2 + -1z2 = 5 + -1z2

Combine like terms: z2 + -1z2 = 0

2iz + 0 = 5 + -1z2

2iz = 5 + -1z2

Divide each side by '2z'.

i = 2.5z-1 + -0.5z

Simplifying

i = 2.5z-1 + -0.5z