Question

let 4n^2 be the largest 3 digit square number where n is a natural number. what is the value of n?​

Answer 1

Step-by-step explanation:

$largest \: 3 \: digit \: number \: is \: 999 \\ 4 {n}^{2} = 999 \\ {n}^{2} = \frac{999}{4} \\ n = 15.8$

$n \: is \: not \: natural$

$so \: no \: natural \: value \: of \: n \: is \\ \: possible \: so \: that \: 4 {n}^{2} be \: the \: largest \: \\ three \: digit \: square \: number$