Let A={0,2,4,6},B={1,2,3,4,5}and C={2,4,6,8}.
Verify that :(AUB)UC=AU(BUC).
Answers
Answered by
2
(U → UNION): All elements in both the sets
(Π → INTERSECTION): common elements from both the sets
A={0,2,4,6},
B={1,2,3,4,5}, and
C={2,4,6,8}
AUB = {0,1,2,3,4,5,6}
Now, (AUB)UC = {0,1,2,3,4,5,6,8}
BUC = {1,2,3,4,5,6,8}
AU(BUC) = {0,1,2,3,4,5,6,8}
Now, (AUB)UC = AU(BUC)
Since, LHS = RHS
Hence proved.
(if you still have any doubt, ask in the comment)
Thankyou!!!
(Π → INTERSECTION): common elements from both the sets
A={0,2,4,6},
B={1,2,3,4,5}, and
C={2,4,6,8}
AUB = {0,1,2,3,4,5,6}
Now, (AUB)UC = {0,1,2,3,4,5,6,8}
BUC = {1,2,3,4,5,6,8}
AU(BUC) = {0,1,2,3,4,5,6,8}
Now, (AUB)UC = AU(BUC)
Since, LHS = RHS
Hence proved.
(if you still have any doubt, ask in the comment)
Thankyou!!!
colourmedia:
thank you
Answered by
11
Answer:
given:
A = 0,2,4,6
B=1,2,3,4,5
C=2,4,6,8
L.H.S = (AUB)UC
(AUB)=(0,2,4,6)U(1,2,3,4,5)
= (0,1,2,3,4,5,6)
(AUB)UC = (0,1,2,3,,4,5,6)U (2,4,6,8)
={0,1,2,3,4,5,6,8}
R.H.SV= AU(BUC)
BUC = (1,2,3,4,5)U(2,4,6,8)
= {1,2,3,4,5,6,8}
AU(BUC) = (0,2,4,6)U ( 1,2,3,4,5,6,8)
{0,1,2,3,4,5,6,8}.....
L.H.S=R.H.S..
H/P
Step-by-step explanation:
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