let A=(1,-1) B=(a,b,c) then number of possible relations from Ato B is a)16 (b) 64 (c)7 (d) 81
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It is given that A={x,y,z} and B={1,2}
∴ A×B={(x,1),(x,2),(y,1),(y,2),(z,1),(z,2)}
Since n(A×B)=6
The number of subsets of A×B is 2 6
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