Let A = {1, 2, 3} , B = {2, 3, 4} , then n[(A*B)intersection (B*A)]= ? where * means multiply
A. 1
B. 2
C. 3
D. 4
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n(AB)=(2,3)
n(BA)=n(AB)
i.e n(BA)=(2,3)
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