Math, asked by zaffarsyed7033, 10 months ago

Let ⃗a = 2î + λ₁jˆ + 3kˆ, ⃗b = 4î + (3 – λ₂)jˆ + 6kˆ and ⃗c = 3î + 6jˆ + (λ₃ – 1)kˆ
be three vectors such that ⃗b = 2⃗a and ⃗a is perpendicular to ⃗c. Then a possible value of (λ₁, λ₂, λ₃) is:
(A) (1, 3, 1) (B) (–1/2, 4, 0)
(C) (1/2, 4, –2)
(D) (1, 5, 1)

Answers

Answered by sprao53413
0

Answer:

Please see the attachment

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