let a= 3- √n, where n is a natural number if 'p' is the least possible value of a then find the value of √ p + 1/ √ p
Answers
Answer:
√2
Step-by-step explanation:
Given in the question that
a = 3 - √n
where n is the natural number and we need to find least possible value of a
1) value of p should not be zero = 1/√0 = undefined
2) value of p should not be negative because √-p = imaginary
Step1
least possible value of √n = 2
Since natural numbers are all positive integers so for least possible value of
n = 4
p = 3 - √4 = 3 - 2
p = 1
Step 2
Plug value p in expression √(p + 1) / √ p
√(p + 1) / √ p
√(1+1) / √1
√2/√1
√2
Answer:
Step-by-step explanation:
P is the smallest value of a
Hence a should be smallest
For that n should be largest
3-√9=0. (0 is not posible)
Hence ,
3-√8 is the smallest value of p
=3-√8
=3-2√2
= 1^2 +(√2)^2 +2×1×√2
= (1+√2)^2
For
√p+1/√p
= √(1+√2)^2 +1/√(1+√2)^2
=1+√2+1/1+√2
=2+√2/1+√2