Question

let a= 3- √n, where n is a natural number if 'p' is the least possible value of a then find the value of √ p + 1/ √ p

Answer 1

Answer:

√2

Step-by-step explanation:

Given in the question that

a = 3 - √n

where n is the natural number and we need to find least possible value of a

1) value of p should not be zero = 1/√0 = undefined

2) value of p should not be negative because √-p = imaginary

Step1

least possible value of √n = 2

Since natural numbers are all positive integers so for least possible value of

n = 4

p = 3 - √4 = 3 - 2

p = 1

Step 2

Plug value p in expression √(p + 1) / √ p

√(p + 1) / √ p

√(1+1) / √1

√2/√1

√2

Answer 2

Answer:

Step-by-step explanation:

P is the smallest value of a

Hence a should be smallest

For that n should be largest

3-√9=0. (0 is not posible)

Hence ,

3-√8 is the smallest value of p

=3-√8

=3-2√2

= 1^2 +(√2)^2 +2×1×√2

= (1+√2)^2

For

√p+1/√p

= √(1+√2)^2 +1/√(1+√2)^2

=1+√2+1/1+√2

=2+√2/1+√2