Question

let a = 5i + 3j+ 4k and b =6i - 8j then |a-b| is equal to

Answer 1

It may be this......

A=5i+3j+4k

B=6i-8j-k

A=root 5square+3square+4square

= root 50

B=root 6square +(-8square)+(-1square)

=root 101

A.B=(5i+3j+4k).(6i-8j-k)

=2

angle between A and B= cos theeta

=A.B/AB

2/root50 root101

Plz mark it as brainlest answer

Answer 2

QUESTION.

let a = 5i + 3j+ 4k and b =6i - 8j then |a-b| is equal to





ANSWER.






GIVEN.


a= 5i+3j+4k


b=6i-8j+0k


here I ,j ,k are vector along x,y,z axis


so,







a - b= 5i+3j+4k- (6i-8j+0k)

= - i+(3+8)j+(4-0)k

= - I+ 11 j +4 k







|a - b|= magnitude of a - b
$\sqrt{ { (- 1)}^{2} + {11}^{2} + {4}^{2} }$






$\sqrt{1 + 121 + 16}$






$= \sqrt{138}$



=11.74