Let a and b be the coefficient of x to the power 3 in (1+x+2x square+3x cube)to the power 4 and (1+x+2x square+3x cube+4xto the power 4)to the power 4 respectively. Then the value of 4a/b is :
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Step-by-step explanation:
We have b= coefficient of x3 in
((1+x+2x2+3x3)+4x4)4
= coefficient of x3 in [4C0(1+x+2x2+3x3)4(4x4)0+ 4C1(1+x+2x2+3x3)3(4x4)1+...]
= coefficient of x3 in (1+x+2x2+3x3)4=
Hence,
.
.
4a/b=4.
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