Question

Let A and B be two sets such that n(A) = 3 and n (B) = 2. If (x, 1), (y, 2), (z, 1) are in A × B, find A and B, where x, y and z are distinct elements.​

Answer 1

$\huge\underline\mathfrak\pink{♡Answer♡}$

Given,

n(A) = 3 and n(B) = 2; and (x, 1), (y, 2), (z, 1) are in A × B.

We know that,

A = Set of first elements of the ordered pair elements of A × B

B = Set of second elements of the ordered pair elements of A × B.

So,

clearly x, y, and z are the elements of A; and

clearly x, y, and z are the elements of A; and1 and 2 are the elements of B.

As n(A) = 3 and n(B) = 2,

it is clear that set A = {x, y, z} and set B = {1, 2}.

Answer 2

$\huge\underline{\overline{\mid{\bold{\red{ANSWER-}}\mid}}}$

Given, A and B are two sets such that n(A) = 3 and n(B) = 2.

(x, 1), (y, 2) and (z, 1) ∈ A × B.

Since (x, 1), (y, 2) and (z, 1) are elements of A × B.

∴ x, y and z are elements of A and 1, 2 are elements of B.

Now, n(A × B) = n (A) × n(B) = 3 × 2 = 6

So, A = {x, y, z} and B = {1, 2}.