Let A and B have 3 and 6 elements respectively. Then the minimum number of elements in
AUB equals
(a) 3 (b) 6 (c) 9 (d) 18
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Solution: (2)
n (A ∪ B) = n (A) + n (B) − n (A ∩ B) = (3 + 6 − 3) = 6. The minimum number of elements in A ∪ B = 6.
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