let A and B the remainder when the polynomials y³ + 2y² - 5ay - 7 and y³ + ay² - 12y + 6 divided by y + 1 and y - 2 if 2 A + B = 6 find a
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y ^3 +2y^2 −5ay−7 leaves a remainder A, when divided by y+1.
So, plugging in y=−1 in the above polynomial, we can find remainder A.
A=−1+2+5a−7=5a−6
y^3+2y^2−5ay−7 leaves a remainder B, when divided by y−2.
So, plugging in y=2 in the above polynomial, we can find remainder A.
B=8+4a−24+6=4a−10
Given, 2A+B=6
10a−12+4a−10=6
14a−22=6
14a=28
a=2
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