Let A and B two sets. If n(A-B)=37,n(B-A)=25,n(AUB) =12, find n(A ∩B)
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Answered by
2
Answer:
(A- B) = 37 = A n B'
B - A) = 25 = B nA '
An B= 37 - 25
= 12
Answered by
1
Answer:
Union of set A and B is ,n(AUB) = 74.
Step-by-step explanation:
here, the given question is wrong ,as n(AUB) cannot be 12 if n(A-B) and n(B-A) are 37 and 25 respectively. therefore will be as,
IfA and B two sets such that n(A-B)=37, n(B-A)=25, n(A∩B) =12, find n(AUB) .
then
n(AUB) = n(A-B) +n(B-A) +n(A∩B)
then ,substitute values given to the equation,
n(A-B)=37n(B-A)=25n(A∩B) =12
n(AUB)=37+25+12=74.
definition
B-A contains elements in A and those elements are not in B.
A-B contains elements in B and tht willnot be in B
AUB means entire elements of A and B
A∩B means elements that are in both set A and B
#SPJ3.
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