Question

Let a and ß be the zeroes of p(x) = 12x2 – 3x - 9.
(a) Find the value of a + B.
(b) Find the value of aß.

Answer 1

Step-by-step explanation:

a+b= -b/a

a+b= -(-3)/12=3/12=1/4

ab= c/a= -9/12= -3/4

so a+b=1/4

and ab= -3/4