Question

Let a and ß be the zeroes of p(x) = 4x2 + 14x - 8.
(a) Find the value of a + ß.
(b) Find the value of aß.

Answer 1

Answer:

(a) -7 /2

(b) -2

Step-by-step explanation:

In this quadratic equation,

a = 4 ( Co efficient of x² )

b = 14 ( Co efficient of x )

c = - 8 ( Constant term )

(a) Sum of roots

= - Co efficient of x /Co efficient of x²

= - b/a = - 14/4

Alpha + Beta = - 7/2

(b) Product of roots

= Constant term / Co efficient of x²

= c/a = - 8 / 4

Alpha × Beta = - 2