Let A,B and C be sets then show that:-
A intersection(B union C)= (A intersection B) union( A intersection C)
Answers
Step-by-step explanation:
- From (1) and (2)
- From (1) and (2) A ∩ (B U C) =(A ∩ B)U(A ∩ C)
Answer:
The correct answer to this question is,
A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C) is verified.
Step-by-step explanation:
Union:
The union of a set consists of all the elements present in the Sets
Intersection:
The intersection of a set consists of the elements which are only common in the sets
Let us take an example and we will verify this question by this example.
A = { 1, 2, 3, 4, 8, 10 }
B = { 2, 3, 5, 7, 9, 10 }
C = { 1, 2, 3, 4, 5, 6 }
Now, L.H.S = A ∩ (B ∪ C)
(B ∪ C) = { 2, 3, 5, 7, 9, 10 } ∪ { 1, 2, 3, 4, 5, 6 }
(B ∪ C) = { 1, 2, 3, 4, 5, 6, 7, 9, 10 }
A ∩ (B ∪ C) = { 1, 2, 3, 4, 8, 10 } ∩ { 1, 2, 3, 4, 5, 6, 7, 9, 10 }
A ∩ (B ∪ C) = { 1, 2, 3, 4, 10 }
Now, R.H.S = (A ∩ B) ∪ (A ∩ C)
(A ∩ B) = { 1, 2, 3, 4, 8, 10 } ∩ { 2, 3, 5, 7, 9, 10 }
(A ∩ B) = { 2, 3, 10 }
(A ∩ C) = { 1, 2, 3, 4, 8, 10 } ∩ { 1, 2, 3, 4, 5, 6 }
(A ∩ C) = { 1, 2, 3, 4 }
(A ∩ B) ∪ (A ∩ C) = { 2, 3, 10 } ∪ { 1, 2, 3, 4 }
(A ∩ B) ∪ (A ∩ C) = { 1, 2, 3, 4, 10}
We can see, L.H.S = R.H.S
∴ A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
Hence we show that A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C) (verified)
Click here for more about the union set:
https://brainly.in/question/7566103
Click here for more about the intersection set:
https://brainly.in/question/29801008