Question

Let a,b and c be the roots of the equation x^3-2x^2+4x+10=0,then find the value of 1/2 (a+2)(b+2)(c+2)

Answer 1

x^3-2×^4×+10=0
3-16=13×10=130
a=130×2=260
b=260×2=520
c=520×2=1040
a=260
b=520
c=1040