Question

Let A be a 4 digit integer. When both the first digit (left most) and the third digit are increased by n, and the second digit and the fourth digit are decreased by n, the new number is n times A. The value of A Is expressed as abab then a+b=?

Answer 1

A+4+N-4 VALUE = AN..

Answer 2

Concept Introduction: Playing with digits and numbers is a part of mathematics.

Given:

We have been Given: A is a four digit integer that is expressed as

$abab$

a is increased by n and b is decreased by n

To Find:

We have to Find:

$a + b =$

Solution:

According to the problem, A is

$abab$

Let the new number be

$x$

therefore

$x = n \times abab = (a + n)(b - n)(a + n)(b - n)$

therefore the value of

$a + b = (a + n) + (b - n) = a + b$

Final Answer: The value of

$a + b = a + b$

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