Question

Let a be an n x n matrix prove that if all the rows sum to m then m is an eigenvalue of a

Answer 1

Answer:

proved buddy

Step-by-step explanation:

now it's just easy buddy just looks complicated it's all just conceptual because ,

by the characterstic equation of a matrix as we multiply the sum of all the elements of a row with an identity matrix it occupies the principal diagonal of the nxn matrix when we substract it from the main matrix A, the sum of all row elements of A will be subtracted from the principal diagonal elements which will be nothing but the negative addition of all other elements other than the principal diagonal elements of matrix A in which by using the column operation we get the 1st column to become 0 eventually the determinant of the whole matrix will become zero