Question

let a be the sum of additive inverse of -2/7 and 3/5 and b be the sum of reciprocal 4/3 and 2/5. Find the product of A and B​

Answer 1

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So , first add -2/7 and 3/5 .

$\frac{ - 2}{7} + \frac{3}{5} = \frac{ - 10 + 21}{35} \\ \\ \frac{11}{35} = \frac{ - 11}{35}$

Now , add 4/3 and 2/5 .

$\frac{4}{3} + \frac{2}{5} = \frac{20 + 6}{15} \\ \\ \frac{26}{15} = \frac{15}{26}$

Now , multiply a and b means multiply -11/35 by 15/26 .

$\frac{ - 11}{35} \times \frac{15}{26} \: = \frac{ - 33}{182}$