Question

let a car start from point i move in a semi circular path in clockwise direction where radius is r and reaches final position f . find distance and displacement

Answer 1

Hii friend,

Here is your answer....

The distance is the overall distance covered during the revolution and the displacement is the shortest distance covered covered during the revolution.

Here for a semi circular path,

Distance= circumference/2

Distance= 2πr/2

Distance= πr

displacement is equal to diameter of the circle.

Displacement= 2R.

Hope this helps you a little!!!
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Answer 2

$\maltese \: \red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

Displacement is the shortest distance between final and Initial position of an object journey.

Whereas the distance is the total path traveled by an object.

For example - The path of one corner to another consecutive corner of a square is the distance.

The diagonal connecting these both points is the displacement path, because in a shape the diagonal is the shortest rather than distance between one corner to other.

$\blue{\mid{\underline{\overline{\textbf{Coming to question :-}}}\mid}}$

In this case it is given that a car starts from point A and moves in a semi - circular (half - circle) path and reaches the other end of semi circle which is point F. Radius of this semi - circular path is r. We have to calculate distance and displacement of car.

Now since the car travels in a semi circle thus, the distance traveled by car is half of full perimeter of a circle.

This will be :

$\maltese \: \frac{2\pi \: r}{2}$

$\maltese \: \cancel \frac{2}{2} \times \pi \: r$

Therefore the distance traveled will be π r.

Now in a semi circle the displacement between one end and second end are at same point of view, this displacement path will be diameter of semicircle.

Diameter is double of radius therefore the displacement will be 2 × radius or diameter.

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BY SCIVIBHANSHU

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