Question

A block of mass 10 kg is released on rough incline plane inclined at an angle 30 degree. Block start descending with acceleration 2 m/s² . Kinetic friction force acting on block is ( take g= 10m/s² )

Answer 1

hope it will be helpful to u........if any doubt u can ask.......

Answer 2

Answer:

Explanation:

a  

down

​  

=2m/s

a  

down

​  

=gsin30−μgcos30

f=μmgcos30

2=  

2

g

​  

−  

m

f

​  

 

m

f

​  

=5−2=3

f=10